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1 4
Continuity of Functions
Continuity Basics
Leeeb
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1 4
Continuity of Functions
Continuity Basics
Leeeb
Intervals of Continuity
From Graph
Continuity
On an Open Interval
Katthhryn Portal
Examples in Videos
of Continuity Editing
Interval
Continuity
Interval Notation and
Continuity
Continuity
On Intervals
Continuous of
Interval
Continuity
at an Interval
Continuation of
Simple
Continuity
and Interval
Find Intervals
of Continuity
Examples of
Good Continuation
Interval of Continuity
Calc
Calculus
Practice in Bengali
0:43
YouTube
Shivang Maths Academy
Q) If 2cos^(β1) π₯ = π¦,then(A) 0β€π¦β€π(B) βπβ€π¦β€π(C) 0β€π¦β€2π(D) βπβ€π² β€ 0 #shivangmathsacademy
CBSE PYQ 2026 π± Most Students Get This WRONG | Inverse Trigonometry Trick π₯ Q) If 2cos^(β1) π₯=π¦, then (A) 0β€π¦β€π (B) βπβ€π¦β€π (C) 0β€π¦β€2π (D) βπβ€π² β€ 0 #class12maths #shivangmathsacademy #cbsemaths #class12th class 12th maths chapter number 2 inverse trigonometric functions class 12 class ...
1.5K views
1 week ago
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Continuity and Limits
1:05
Draw the graph of π(π₯)=π ππ^(β1) π₯, π₯β[β1/β2, 1/β2]. Also, write range of f(x). #trigonometry
YouTube
Shivang Maths Academy
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1:50
Q) If π ππ πππ‘^(β1) (π₯+1)]=πππ (tan^(β1) π₯), π‘βππ ππππ π₯.#class12maths #shivang
YouTube
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0:51
Q) Simplify : tan^(β1) {β((1βcosπ₯)/(1+cosπ₯))}}#class12maths #shivangmathsacademy #cbsemaths
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1:52
Q) The value of tan[1/2 cos^(β1) (β5/3)] is (a) (3+β5)/2 (b) (3ββ5)/2(c) (β3+βg5)/2(d) (β3ββ5)/2
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Q) Simplify : tan^(β1) ((cos2π₯βsin2π₯)/(cos2π₯+sin2π₯)),0=π₯=π/4..#class12maths #shivangmathsaca
YouTube
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1:50
Q) The function π defined by π(π₯)={ (π₯,f π₯β€1 5, if π₯= 1 is not continuous at(A) x=0(B) π₯
YouTube
Shivang Maths Academy
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2:22
Find k so that π(π₯)={((π₯^2β2π₯β3)/(π₯+1), π₯β β1 π, π₯=β1) is continuous at x=β1.#cbse2027 #maths
YouTube
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Q) The value of tan[1/2 cos^(β1) (β5/3)] is (a) (3+β5)/2 (b) (3ββ5)/2(c) (β3+βg5)/2(d) (β3ββ5)/2
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Q) Check whether function f(x) defined as f(π₯)={((|π₯β3|)/(2(π₯β3)), π₯=3 (π₯β6)/6,π₯β₯3) Is
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YouTube
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1:07
Q) If π(π₯)={(sinπ₯/π₯+cosπ₯, π₯β 0 π, π₯=0) is continuous at π₯=0, then the value of π is :
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Q) Simplify : tan^(β1) {β((1βcosπ₯)/(1+cosπ₯))}}#class12maths #shivangmathsacademy #cbsemaths
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Q) The function π defined by π(π₯)={ (π₯,f π₯β€1 5, if π₯= 1 is not continuous at(A) x=0(B) π₯
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2 weeks ago
YouTube
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Find k so that π(π₯)={((π₯^2β2π₯β3)/(π₯+1), π₯β β1 π, π₯=β1) is continuous at x=β1.#cbse2027 #maths
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Q) Simplify :sin^(β1) (5/13 cosπ₯+12/13 sinπ₯)#class12maths #shivangmathsacademy #cbsemaths
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Q) If π(π₯)={(3π₯β2, 0β€π₯β€1 2π₯^2+ππ₯, 1β€π₯β€2) is continuous for π₯β(0,2), then a is equal to
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2:13
Q) If π(π₯)={ ((π₯^2β4π₯β5)/(π₯+1), π₯β β1 π,&π₯=β1 is continuous at π₯=β1, then the value of π i
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Q) Simplify: ππ¨π¬^(βπ) π±+ππ¨π¬^(βπ) [π±/π+β(πβππ±^π )/π]; π/πβ€π±β€π #cbsemaths #maths
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If π(π₯)={ ((sin^2 ππ₯)/π₯^2 if π₯β 0 1 , if π₯=0) is continuous at π₯=0, then the value of ' π β
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1:46
Q) Find the value of π, so that π(π₯)={(πcosπ₯/(πβ2π₯), if π₯β π/2@3, if π₯=π/2) is continu
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Q) Evaluate sin[cos^(β1) cos(7π/6)] #shivangmathsacademy #cbsemaths #class12maths #maths
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Q) Domain of π ππ^(β1) (2π₯^2β3) is (A) (β1,0)βͺ(1,β2)(B) (ββ2,β1)βͺ(0,1)(C) [ββ2,β1]βͺ[1,β2](D) (β
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1:53
Q) If π(π₯)={((1βsin^3 π₯)/(3cos^2 π₯), for π₯β π/2 π, for π₯=π/2) is continuous at π₯=π/2, t
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